The digits of a 2-digit number differ by 3. If the digits are interchanged and the
resulting number is added to the original number, we get 143. What can be the
original number?
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Answer:
The original number is 85
Step-by-step explanation:
Let the digit in unit's place be y and the digit in the ten's place be x.
x-y = 3 (equation 1)
Therefore, number = 10x + y
If digits are interchanged, number = 10y + x.
(10x + y) + (10y + x) = 143
10x + x + 10y + y = 143
11x + 11y = 143
x + y = 13 (equation 2)
On adding the two equations:
x+y=13
x-y=3
_____
2x=16
x=8.
y = 5
Therefore, the original number = 85
I hope this helped, let me know if anything's wrong!
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