Math, asked by potkelxi3, 3 days ago

the digits of a 2 digit number differ by 3. if the digits are interchanged and the new number is added to the original number, the result is 143. What is the original number? ​

Answers

Answered by Prettyprincess96
2

Answer:Solution

Let the digits of the number be a and b such that the number is (10a+b).

According to the question,

a−b=3 or b−a=3 (1)

10a+b+10b+a=143

a+b=13 (2)

Solving both the equations, we have

a=8 and b=5 or a=5 and b=8

Therefore, the required number is 85 or 58.

Step-by-step explanation:

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Answered by mahaswinsai14
0

Answer:

x = 8

y = 5

the original number is 85

Step-by-step explanation:

let the first digit be x

let the second digit be y

x - y = 3

(10x + y) + (10y + x) = 143

11x + 11y = 143

x = 3 + y

11( 3 + y ) + 11y = 143

33 + 11y + 11y = 143

22y = 110

y = 110/22

y = 5

x - 5 = 3

x = 3 + 8

x = 8

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