the digits of a 2 digit number differ by 3. ifhe digits are interchanged and the resulting new number is added to the original number, you get 143. what canbe the original number
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Let, tens digit number be x
ones digit number be (x-3)
Original number = {10x+(x-3)}
After interchanging the digits, the new number
= {10(x-3)+x}
ATP
{10(x-3)+x}+{10x+(x-3)} = 143
=) (10x-30+x)+(10x+x-3) = 143
=) 10x-30+x+10x+x-3 = 143
=) 22x = 143+30+3
=) 22x = 176
=) x = 8
Ans:-Original number = {(10×8)+(8-3)} = (80+5) = 85
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