Hindi, asked by KKJ1209, 8 months ago

The digits of a 2 digit number differ by 5. If the digits are interchanged and the resulting number is added to the original number, we get 99. Find the original number.

Answers

Answered by Anonymous
0

Answer:

Explanation:

Let the one digit number be x

And tens digit number be y

(y>x)

No. 10y+x

And interchanged no. =10x+y

According to the question,

x-y=5.............¡

10y+x+10x+y=99

=>11y+11x=99

=>x+y=9..........¡¡

Now ¡¡-¡ we get,

x+y-(x-y) =9-5

=>2y=4

=>y=2

Putting y=2in equation ¡

x-y=5

=>x-2=5

=>x=7

The number is

10y+x=10×2+7=27.

Answered by karpagamss9
0

Answer:

27

Explanation:

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