The digits of a 2 digit number differ by 5. If the digits are interchanged and the resulting number is added to the original number, we get 99. Find the original number.
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Answered by
0
Answer:
Explanation:
Let the one digit number be x
And tens digit number be y
(y>x)
No. 10y+x
And interchanged no. =10x+y
According to the question,
x-y=5.............¡
10y+x+10x+y=99
=>11y+11x=99
=>x+y=9..........¡¡
Now ¡¡-¡ we get,
x+y-(x-y) =9-5
=>2y=4
=>y=2
Putting y=2in equation ¡
x-y=5
=>x-2=5
=>x=7
The number is
10y+x=10×2+7=27.
Answered by
0
Answer:
27
Explanation:
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