Question

The digits of a positive integer having three digits are in A.P and the sum is 15. The number obtained its reversing digits is 594 less than the originl number. Find the number

Answer 1

Let no. be in form (a-d)a(a+d)
(a-d) + a + (a+d) = 15
3a = 15
a = 5
100(a-d) + 10a + a+d - 594 = 100(a+d) + 10a + (a-d)
111a - 99d -594 = 111a + 99d
-198d = 594
d = -3
(a-d)a(a+d) no will be 852.