Question

the digits of a positive integer having three digits are in AP and their sum is 15 the number obtained by reversing the digit is 594 less than the original number find the number. ​

Answer 1

Answer: 852

Step-by-step explanation:

let a, b and c be the hundreds, tens and ones digit respectively

since a, b and c are in AP and their sum is 15, then 3b=15

so b=5

The number is 100a+10b+c

Given, the number obtained by reversing the digits is 594 less than the original number

So 100a+10b+c-594=100c+10b+a

99a-99c=594

a-c=6-----(1)

a+c=15-5=10----(2)

Solving (1) and (2), we get

a=8 and c=2

So the number is 852