Question

the digits of a positive three digit number are in AP and their sum is 15 the number obtained by reversing the digits is 594 less than the original number find the number

can this question answer be 591 if not why??

Answer 1

Step-by-step explanation:

Hence, the number formed by the digits = 100(8) + 10(5) + 1(2) = 852. The digit of positive integers having 3-digit number are in AP and their sum is 15 . Number obtained by reversing the digit is 594 less than the original number

Answer 2

Answer:

your solution is as follows

pls mark it as brainliest

Step-by-step explanation:

$to \: find : three - digit \: number \\ \\ let \: the \: three \: numbers \: in \: an \: AP \: be \\ (a + d),a,(a - d) \\ \\ so \: the \: three \: digit \: number \: \\ formed \: with \: these \: digits \: is \\ 100(a + d) + 10a + a - d \\ = 100a +10 a + a + 100d - d \\ = 111a + 99d \\ \\ number \: obtained \: by \: reversing \\ same \: digits \: would \: be \\ 100(a - d) + 10a + a + d \\ = 100a + 10a + a - 100d + d \\ = 111a - 99d \\ \\ according \: to \: first \: condition \\ a + d + a - d = 15 \\ 3a = 15 \\ a = 5 \\ \\ according \: to \: second \: condition \\ 111a - 99d = 111a + 99d - 594 \\ 99d + 99d = 594 \\ 198d = 594 \\ d = 3$

$thus \: then \\ (a + d) = 3 + 5 = 8 \\ a = 5 \\ (a - d) = 5 - 3 = 2 \\ \\ our \: required \: three \: digit \: number \: was \\ 100(a + d) + 10a + a - d \\ = (100 \times 8) + 10(5) + 2 \\ = 800 + 50 + 2 \\ = 852$