Question

the digits of a that is a Circuit 2 digit number differ by 3 if the digits are interchanged and the resulting is added to the original number we get 143 find the original number

Answer 1

Let the units place digit be x and tens place digit be y

so the number is 10y + x

If the digits are interchanged then number becomes

10x + y

By the condition given in your question we get equations

10y + x + 10x + y = 143

11y + 11x = 143

Dividing by 11

y + x = 13. ..... ( l )

y - x = 3. .... ( 'll )

By adding equations ( l ) & ( 'll ) we get

2y = 16

y = 8

putting y = 8 in equation ( l ) we get

8 + x = 13

x = 13 - 8

x = 5

so the number is

10y + x = 10 × 8 + 5

= 80 + 5

= 85

so your required number is 85