The digits of a three digit natural number are in AP and their sum is The number obtained by reversing the digits is 396 less than the original number. Find the number.
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Let 3 digit be X, Y and Z
100X + 10Y + Z = 100Z + 10Y + X + 396
99 X = 99 Z + 396
X = Z + 4
Now,
X, Y and Z are in AP
Z = X + 2d
Z = Z + 4 + 2d
d = -2
So, it can be
972 & 279
864 & 468
And so on
864 and 468 have difference of 396
Thus number is 396
100X + 10Y + Z = 100Z + 10Y + X + 396
99 X = 99 Z + 396
X = Z + 4
Now,
X, Y and Z are in AP
Z = X + 2d
Z = Z + 4 + 2d
d = -2
So, it can be
972 & 279
864 & 468
And so on
864 and 468 have difference of 396
Thus number is 396
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