The digits of a three-digit number A are written in the reverse order to form another three-digit number B. If B > A and B – A is perfectly divisible by 7, then how many possible values A can have ?
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Answer: The number is in the form of 99×7 (co'prime number )
There are some possible values like
108 , 168 , 299, 299 ,
801-108=693/7 R=0
861-168=693/7 R=0
952-259=693/7 R=0
992-299=693/7 R=0
Hope it helps! !
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