The digits of a two-digit number are in the ratio 2 : 3 and the number obtained by interchanging the digits
is greater than the original number by 27. What is the original number?
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Answered by
2
Answer:69
Step-by-step explanation:
Let the digits are 2x and 3x .
If 2x is unit-place digit and 3x is tenth-place digit, then the number is (3x)10+2x = 32x
By reversing the digits, number obtained is (2x)10 + 3x = 23x
Since the difference is 27, we have 9x = 27 or x = 3
hence digits are 6 and 9 and original number is 69
Step-by-step explanation:
Answered by
0
Answer:
could u please say what should be found
Step-by-step explanation:
pls mention what to be found in the comment box
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