Question

The digits of a two-digit number are in the ratio 2:3 and the number obtained by interchanging the digits
is greater than the original number by 27. What is the original number?
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Answer 1

Answer:

The original number is 69

Solution:

Let the digits are 2x and 3x.

If 2x is in unit place and 3x is in tenth place digit, then the number is 10 \times(3 x)+2 x=32 x10×(3x)+2x=32x

By reversing the digits, number obtained is 10 \times(2 x)+3 x=23 x10×(2x)+3x=23x

As give the difference is 27,

32x - 23x = 2732x−23x=27

9x = 279x=27

x=3x=3

So, the digits are 6 and 9, and the number is 69.

Answer 2

Answer:

69

any two digit number are in the form 10m+n, If the number is mm ( eg: 23 = 2×10+3)