Question

The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.what is the original number?

Answer 1

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Answer 2

Answer:

The original number is 69

Solution:

Let the digits are 2x and 3x.

If 2x is in unit place and 3x is in tenth place digit, then the number is $10 \times(3 x)+2 x=32 x$

By reversing the digits, number obtained is $10 \times(2 x)+3 x=23 x$

As give the difference is 27,

$32x - 23x = 27$

$9x = 27$

$x=3$

So, the digits are 6 and 9, and the number is 69.