Question

The digits of a two-digit number differ by 3. If digits are interchanged and the resulting number is added to the original number, we get 121. Find the original number.​

Answer 1

Given:-

• Two digits of a number differ by 3.
• If the original number is added to the number we obtain after reversing it, the sum is 121.

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To Find:-

• The Original Number.

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Solution:-

Let,

• the digits be x and x + 3.

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Here,

→ Original Number = 10x + (x + 3)

→ On reversing = 10(x + 3) + x

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According to the question,

→ Original Number + Number after reversing = 121

→ {10x + (x+3)} + {10(x+3) + x} = 121

→ {10x + x + 3} + {10x + 30 + x} = 121

→ 10x + x + 3 + 10x + 30 + x = 121

→ 11x + 3 + 11x + 30 = 121

→ 22x + 33 = 121

→ (22x + 33)/11 = 121/11

→ 2x + 3 = 11

→ 2x = 11 - 3

→ x = 8/2

→ x = 4

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Therefore,

• Original Number = 10x + (x + 3) = 10(4) + (4 + 3) = 40 + 7 = 47

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Hence,

• The original Number is 47.

Answer 2

Answer:

Hi I hope this will help

Step-by-step explanation:

do it on your own

that will help you more than just asking to question on the internet

:/