The digits of a two-digit number differ by 3. If digits are interchanged and the resulting number is added to the original number, we get 121. Find the original number.
Answers
Answer:
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Step-by-step explanation:
Let first number be x
Other number will be x+3
According to question
10x+(x+3)+10(x+3)+x=143
10x+x+10x+x+3+30=143
22x=110
x=5
digit will be 58
Step-by-step explanation:
Let us take the two digit number such that the digit in the units place is x. The digit
in the tens place differs from x by 3. Let us take it as x + 3. So the two-digit number is
10 (x + 3) + x = 10x + 30 + x = 11x + 30.
With interchange of digits, the resulting two-digit number will be 10x + (x + 3) = 11x + 3
If we add these two two-digit numbers, their sum is
(11x + 30) + (11x + 3) = 11x + 11x + 30 + 3 = 22x + 33
It is given that the sum is 121.
Therefore, 22x + 33 = 121
22x = 121 – 33
22x = 88
x=4
The units digit is 4 and therefore the tens digit is 4 + 3 = 7.
Hence, the number is 74 or 47.