The digits of a two-digit number differ by 3. If digits are interchanged and the resulting number is added to the original number, we get 121. Find the original number.
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We Have :-
a two digit number a two digit number
To Find :-
the original number
Solution :-
second digit becomes x+3
acc to the question now
10(x)+(x+3)+10(x+3)+x=121
10x+x+3+10x+30+x=121
11x+3+11x+30=121
22x+33=121
11(2x+3)=121
2x+3= 121/11
x=4
x+3=4+3=7
- so the original number is 47
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