The digits of a two-digit number differ by 3. If digits are interchanged and the resulting number is added to the original number, we get 121. Find the original number.
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Let the two digit numbers be xy
The digit of a two digit number differ by 3
Hence, x-y = 3 (1)
the digits are interchanged and the resulting numbers is added to the original number we get 121.
10x + y + 10y + x = 121
11x + 11y = 121
x + y = 11 (2)
Solving 1 and 2 we get x = 7 and y = 4
Hence, the original number is 74.
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