The digits of a two digit number differ by 3 .If the digits are interchanged and added to the original number we get 121. Find the original number ?
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Answer:
One’s place => 7
Tens place => 4
Step-by-step explanation:
Let digit in one’s place be ‘x’ and tens place be ‘y’.
x-y=3
Original number => 10x+y
When digits are interchanged=> 10y+x
According to given statement,
10x+y + 10y+x = 121
11(x+y) = 121
x+y = 11
x+y = 11. So y = 11-x
x-y = 3
x-(11-x) = 3
x-11+x = 3
2x = 3+11
So, x=7
Digit in one’s place is 7 and tens place is 4
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