The digits of a two digit number differ by
3 . If the digits are interchanged and the resulting no.is added to original no.we get 143 . What can be the no. ?
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Answer:
Let ones digit be x
Lrt tens digit be 3 - x
2digit no =10*[tens digit] +ones digit
=10*[3-x]+x
30-30x+x
30-29x
Reversed
10*[ones digit] +ones digit
10*[x]+3-x
10x +3-x
9x+3
Atq
30-20x+143=9x+3
173-20x=9x+3
173-3=9x+20x
170=29x
170/29=x
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