Question

The digits of a two-digit number differ by 3. If the digits are inter changed and the resulting number is added to the original number, we get 143. What can be the original number?​

Answer 1

$\large \fbox{ \: \sf \blue{ A}n{s}w{e}r \: \sf \underline}$

$\\ \sf \hookrightarrow 85$

$\Huge{\underline{\underline{\blue{\mathfrak{Solution}}}}}$

Let the two digit number be x and y.

 

The digit of a two digit number differ by 3.

Hence, x - y = 3________(i)

The digit are interchanged and the resulting number is added to the original number we get 143.

10x + y + 10y + x = 143

11x + 11y = 143

x + y = 13_____________(ii)

Solving (i) and (ii) we get x = 8 and y = 5

${\sf{Hence,\ the\ original\ number\ is\ 85.}}$

Answer 2

Answer:85

Step-by-step explanation:

Let the two digit number be 10x+y.

The digit of a two digit number differ by 3.

Hence, x - y = 3________(i)

The digit are interchanged and the resulting number is added to the original number we get 143.

10x + y + 10y + x = 143

11x + 11y = 143

x + y = 13_____________(ii)

Solving (i) and (ii) we get x = 8 and y = 5

Therefore the number is 85