the digits of a two-digit number differ by 3 if the digits are interchanged and the two numbers are added the sum is 77 find the numbers
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Answer:
58
Step-by-step explanation:
Let the digit at units place be x
Let the digit at tens place be x + 3
10(x + 3) + x
When digits interchanged, the number becomes 10x + x + 3
According to the question,
10(x + 3) + x + 10x + x + 3 = 77
10x + 30 + 12x + 3 = 77
22x + 33 = 77
22x = 77 - 33
22x = 44
x = 44/22
x = 2
∴ The number = 10(x + 3) + x = 10 * 5 + 3 + 5 = 50 + 3 + 5 = 53 + 5 = 58
∴ The number is 58
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