Question

The digits of a two-digit number differ by 3. If the digits are interchanged and the resulting number is added to the original number, the sum is 143. What is the original number?

Answer 1

let x be tens digit
let y be unit digit
a/q, x-y = 3
original no. is 10x+y
reversed no. is 10y+x
now, 10y+x+10x+y= 143
11x+11y=143
x+y= 13
now add the 2 eq. formed,
x+y=13
x-y=3
2x=16
x=8
now, 8+y=13
y=5
therefore, original no. is 85
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