Question

the digits of a two digit number differ by 3.If the digits are interchanged and added to the original number the number obtained is 143. Find both the numbers.

Answer 1

X-Y = 3. X = 3+y-----(1)
(10y+x) +(10x+y) = 143
10y+x+10x+y = 143
11x+11y = 143
Using equation (1)
11(3+y)+11y = 143
33+11y+11y = 143
22y = 143-33
Y = 110/22
Y = 55
Using equation (1)
X = 3+y
X = 3+55
X = 58

HOPE IT's CORRECT
IF SO THEN PLZ MARK ME THE BRAINLIEST

Answer 2

★ Ello ★

here is your answer !!!

let the number at unit place be y

and 10 th place be x



hence , the number is formed is => 10 x + y


now digit's are interchange we got

10y + x


according to question !


the sum of their is. 143


10x + y + 10y + x = 143

11 ( x + y ) = 143


x + y = 13 -----------------(1)


according to question

digit's are differ by = 3


so. case 1

x - y = 3 ----------------(2)

y -x = 3 --------------------(3 )


=> from equation 1 and 2 we get

x + y = 13
x - y = 3
(+ ) ( + ) = (+)
==========
2x = 16

x = 8

y = 5


hence , the number obtained is 10 x + y
=> 10 × 8 + 5

=> 85


now ,

from equation 1 and 3 we are get


x + y = 13
y - x = 3
=========
2y = 16


y = 8


x = 5


hence the number formed is 10x + y

=> 10 × 5 + 8

=> 58


hence the two numbers are possible that is

85 and 58



★hope it helps you dear ★


$thanks$