the digits of a two digit number differ by 3.If the digits are interchanged and added to the original number the number obtained is 143. Find both the numbers.(use only one variable)
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The answer is given below :
Since, the difference between the digits of the number is 3, we consider the numbers as (x + 3) and x at tens and ones place respectively.
where (x + 3) - x = 3.
Then, the number is
= 10(x + 3) + x
= 10x + 30 + x
= (11x + 30)
When the digits are interchanged, the number is
= 10x + (x + 3)
= (11x + 3)
By the given condition,
Original number + New number = 143
⇒ (11x + 30) + (11x + 3) = 143
⇒ 22x + 33 = 143
⇒ 22x = 143 - 33
⇒ 22x = 110
⇒ x = 110/22
⇒ x = 5
So, the digit at ones place is 5 and the digit is tens place is (5 + 3) = 8.
So, the numbers are 85 and 58.
Thank you for your question.
Since, the difference between the digits of the number is 3, we consider the numbers as (x + 3) and x at tens and ones place respectively.
where (x + 3) - x = 3.
Then, the number is
= 10(x + 3) + x
= 10x + 30 + x
= (11x + 30)
When the digits are interchanged, the number is
= 10x + (x + 3)
= (11x + 3)
By the given condition,
Original number + New number = 143
⇒ (11x + 30) + (11x + 3) = 143
⇒ 22x + 33 = 143
⇒ 22x = 143 - 33
⇒ 22x = 110
⇒ x = 110/22
⇒ x = 5
So, the digit at ones place is 5 and the digit is tens place is (5 + 3) = 8.
So, the numbers are 85 and 58.
Thank you for your question.
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