The digits of a two digit number differ by 3. if the digits are interchanged and the resulting no. is added to the original no. we get 121. Find the original number ?
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Answer:
Step-by-step explanation:
Let the number be 10x + (x-3)
Interchanged = 10(x-3) + x
Therefore we have,
10x + (x-3) + 10(x-3) + x = 121
10x + x-3 + 10x - 30 + x = 121
10x + x + x + 10x - 30 - 3 = 121
22x -33 = 121
22x = 154
x = 154/22
x = 7
Therefore the number is 74
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