Question

The digits of a two digit number differ by 3. If the digits are interchanged and the two numbers are added, their sum is 77. Find the numbers.

Answer 1

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Answer 2

VERIFIED ANSWER

Let

• Ones digit be x
• Tens digits be y
• The number = 10y + x

To Find

• The number = ?

Solution:-

• The difference of two digits no = 3
• X - y = 3 ------(i)
• Digits reversing it sum = 77
• 10y + x + 10x + y = 77
• 11x + 11y = 77
• Dividing by 11 on both sides

X + y = 11 -----(ii)

• By adding eq we get

x - y = 3

x + y = 11

• By Solving we get

2x = 14 => x = 7

• Putting the value of x = 7 in eq 1

X - y = 3

7 - y = 3 => -y = 3-7 = > y = 4

Hence, the required no

= 10y + x

= 10×4 + 7 = 47

Thanks