Question

The digits of a two-digit number differ by 3. If the digits are interchanged,
and the resulting number is added to the original number, we get 143. What can be the
original number?

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Answer 1

Answer:

The digits are interchange

$xy \: + \: yx \: = 143$

The tens place is

$10(x + 3) + x = 10x + 30 + x$

$= 11x + 30$

when we interchange the digits , the result two digit number will be

$10x \: + (x + 3) = 10x + x + 3$

$= 11x \: + 3$

$therefore \: .. \: 11x + 30 + 11x + 3 = 143$

$22x + 33 = 143$

$22x = 143 - 33$

$22x = 110$

$x = \frac{110}{22} = 5$

$x = 5$

The original number is 10(x+3)+x

$= 10(5 + 3) + 5$

$10(18) + 5$

$= 80 + 5 = 85$

Therefore , Interchanged number is ,

$= 10 \times x + (x + 3)$

$= 10 \times 5 + (5 + 3)$

$= 50 + 8$

$= 58$

hope this helps u :)

Answer 2

Answer:

refer to the attachment plz