The digits of a two digit number differ by 3
If the digits are interchanged and the resulting number is added to the original number, we
get 143. What can be the original number?
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Answered by
3
Answer:
Step-by-step explanation:
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archanavchopda:
Please do it in one variable
Answered by
4
let the original no. be 10x+(x+3)=11x+3
so the new no.=10(x+3)+x=10x+30+x=11x+30
it is given that their sum is 143
so,
(11x+3)+(11x+30)=143
22x+33. =143
22x. =143-33
22x. =110
x. =110/22
x=5
so the no. = 10×5+(5+3)
=58
so the new no.=10(x+3)+x=10x+30+x=11x+30
it is given that their sum is 143
so,
(11x+3)+(11x+30)=143
22x+33. =143
22x. =143-33
22x. =110
x. =110/22
x=5
so the no. = 10×5+(5+3)
=58
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