The digits of a two digit number differ by 5. If the digits are interchanged and the
resulting number is added to the original number, we get 77. Find the original number.
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Heya!!
Any two digit number say ( ab ) can be written as 10a + b
=>
Let the required number be xy
ACCORDING TO THE QUESTION
x - y = 5 .... Equation ( i )
And
10x + y + 10y + x = 77
Becoz original number is 10x + y And the number obtained by interchanging the digits is 10y + x
=>
11x + 11y = 77
=>
x + y = 7 .... Equation ( ii )
Now, Add both the Equations ( i and ii ) we get
2x = 12
x = 6 And y = 1
So, the origin number is 10×6 + 1 = 61
Any two digit number say ( ab ) can be written as 10a + b
=>
Let the required number be xy
ACCORDING TO THE QUESTION
x - y = 5 .... Equation ( i )
And
10x + y + 10y + x = 77
Becoz original number is 10x + y And the number obtained by interchanging the digits is 10y + x
=>
11x + 11y = 77
=>
x + y = 7 .... Equation ( ii )
Now, Add both the Equations ( i and ii ) we get
2x = 12
x = 6 And y = 1
So, the origin number is 10×6 + 1 = 61
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