The digits of a two digit number differ by three. If the digits are interchanged and the resulting number is added to the original number we get 143. What can be the original number?
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A two digit number can be written as -> 10x + y .
x -> first digit and y -> second digit.
Now ,
The digits are differ by 3 i.e,
| x - y | = 3
The sum of number and the number when its digits are interchanged is 143 .
( 10x + y ) + ( 10y + x) = 143
i.e ,
x + y = 13 .
If you take x - y = 3 then,
x = 8 & y = 5 and the number will be 85 .
And if you take x - y = -3 then,
x = 5 & y = 8 and the number will be 58.
Hope it helps you...
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