Math, asked by Naidubabu4137, 1 year ago

The digits of a two digit number is differ by 3 if the digits are interchanged and the resulting number is added to the original number we get 143 that can be the original number

Answers

Answered by atharvvtiwari
32

Answer:

58 or 85

Step-by-step explanation:

In the attachment.. Hope it's helpful..

Attachments:
Answered by raunakthanvir
15

Answer:

58  or 85

Step-by-step explanation:

let us all consider the tens digit number of the original number as 10x and the ones digit number as x .

so ,here we can see as we read above that these two digits differ by 3 which means 10x-x (or you can say that 11x as)=3

we can take that as (i am saying about the 3 ) -3 .So as we know that once a number is transposed from LHS TO RHS OR RHS TO LHS we obtain the opposite of the operator given to the number if take an example the result -3 which we have got in this equation is said to be +3 when we transpose

so guys we obtain ,10x+(x+3)

so these italicised words are soooo important

let the newly formed interchanged number be 10(x+3)+x

so

here

10x+(x+3) +10(x+3)+x gives 143

11x+3+10x+30+x gives 143

here

22x+33 gives 143

by transposing the 33

we obtain

143-33=22x

110=22x

therefore

x=5

so the original number is

10x+x+3

50+5+3

which is 58

it could be 85 also

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