The digits of a two-digits number are in the ratio 2:3and the number obtained by interchange the digits is greater than the original number by 27.what is the original number?
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Answer:
given ratio = 2:3
let the ratio be x
unit place = 2x
tenth place = 3x
= 3x×10+2x
=32x
after Interchanging the digits
unit place = 3x
tenth place =2x
=2x×10+3x
=23x
difference given is 27
so,
according to the question ,
32x - 23x = 27
9x=27
x=3
unit place = 2x = 2×3= 6
tenth place = 3x = 3×3 = 9
so , the no. formed is. 69
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