Question

The digits of a two-digits number are in the ratio 2:3and the number obtained by interchange the digits is greater than the original number by 27.what is the original number? ​

Answer 1

Answer:

given ratio = 2:3

let the ratio be x

unit place = 2x

tenth place = 3x

= 3x×10+2x

=32x

after Interchanging the digits

unit place = 3x

tenth place =2x

=2x×10+3x

=23x

difference given is 27

so,

according to the question ,

32x - 23x = 27

9x=27

x=3

unit place = 2x = 2×3= 6

tenth place = 3x = 3×3 = 9

so , the no. formed is. 69

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