Math, asked by Manimalaharitha, 7 hours ago

the digits of a two digits number differ by 3. if digits are interchanged and the resulting number is added to the original number,we get 121. find the original number​

Answers

Answered by vaibhavkhapare73
1

Answer:

hope my answer is correct

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Answered by navyakrishnan41
1

Step-by-step explanation:

take the two digit numbers such that the digit in the unit place is x. the digit in the tens place differs from x by 3. let's take it as X + 3. so the two digit number is

10(x+3)+x=10x+30+x=11x+30.

with interchange of digits, the resulting two-digit number will be 10x + (x+3)=11x+3

if we add these two- digit numbers, their sum is

(11x+30)+(11×+3)=11x+11x+30+3=22x+33

it is given that the sum is 121

therefore, 22x+33 = 121

22 x = 121 - 33

22 x= 88

x=4

the units digit is 4 and therefore the tens digit is 4+3 equal 7

Hence, the number is 74 or 47.

Hope it helps you!!!!

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