Question

The digits of a two digits number differ by 3. if the digits are interchanged and the resulting number is added to the original number, we get 99. What can be the original number?.​

Answer 1

$<b><i>$ hello☺️

Let the tens digit be =x

And once digit be = x-3

[ We know that a 2 digit number can be written as (a)10 +b]

So,

➡️(x)10 + x - 3

➡️10x +x - 3

➡️ 11x - 3 ==> equation.1

When the digits gets reversed ⤵️

➡️ (x-3)10 +x

➡️ 10x - 30 +x

➡️ 11x - 30 ==>equation.2


ACCORDING TO QUESTION :--
==>11x - 3 + 11x - 30= 99

==> 11x +11x - 3-30=99

==> 22x -33 = 99

==> 22x = 99+33

==> 22x = 132

==> x = 132/22

==> X = 6

SO,

The original number ⤵️

➡️(X)10 + x - 3

➡️(6)10 + 6 - 3

➡️ 60 +3

➡️63 Ans.

⭐VERIFY ⤵️⤵️

(x) + 99 = 132

63 + 99 = 132

132 = 132

Answer 2

Solution is in the attachment..