The digits of a two digits number differ by 3. if the digits are interchanged and the resulting number is added to the original number, we get 99. What can be the original number?.
Answers
Answered by
1
The answer is 45(original no.)
please mark my answer as brainliest
please mark my answer as brainliest
poonam3863:
63
Answered by
1
The sum of a two-digit number and the number obtained by interchanging the digits is 11 times the sum of the digits.
Which means,
(10x + y) + (10y + x) = 11(x + y)
The answer is both 10x + y and 10y + x.
Here,
11(x + y) = 99
⇒ x + y = 9 → (1)
Also, given that,
x - y = 3 → (2)
(1) + (2)
⇒ (x + y) + (x - y) = 9 + 3
⇒ 2x = 12
⇒ x = 6
(1) - (2)
⇒ (x + y) - (x - y) = 9 - 3
⇒ 2y = 6
⇒ y = 3
So the original number is,
10x + y = 10 × 6 + 3 = 60 + 3 = 63
and,
10y + x = 10 × 3 + 6 = 36
So the answer is either 63 or 36.
Hope this helps. Plz mark it as the brainliest.
Thank you. :-))
Similar questions