Question

The digits of two digit number differ by 3. If the digits are interchanged and the resulting number is added to the original number, we get 143. What can be original number.

Answer 1

Hey

Here is your answer,

Let the tens place digit be a and units place digit be b.
So, the actual number will be 10a + b
Digits after interchanging = 10b+a

a- b = 3 ....(i)

10a + b + 10b + a = 143

11a + 11b = 143

a+ b = 13....(ii)

Adding equation (i) and (ii)
we get :

2a =. 16
a= 8

Putting value of a in equation (i) we get:

a - b = 3
8 - b = 3
b = 8 - 3
b = 5

Putting value of a and b in 10a + b
we get :

10(8) + 5 = 85

The original number is 85.

Hope it helps you!

Answer 2

here your answer 85. .