Question

The digits of two digit number differ by 3.If the digits are interchanged and two numbers are added, their sum is 77.Find the numbers.

Answer 1

$hey mate here is your answer$

let the digit at unit's place be then the digit at ten's place be x+3 10(x+3) + x if the digits are interchanged then 10(x) +(x+3) on adding these two equation we get 77 10(x+3) + x + 10(x) + (x+3) = 7722x + 33 =77 22x = 44 x=2 then digit at ten's plce is 2+3=5   numbers =52, 25

Answer 2

Your Answer is here

Solution . Let the one place digit be X

And ten's place digit X+3

Number formed= 10(X+3)+X
= 10X+30+X=11X+30

on interchanging the digits ...
one's place= X+3 and
ten's place= X

Number formed=10(X)+X+3
= 10X+X+3=11X+3
According to the given question,
on adding both numbers....

11X+30+11X+3=77
22X+33=77
22X=77-33
22X=44
X=2

So the original no. is 11×2+30=52
Interchanged no. is 11×2+3=25
Hope this helps

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