Math, asked by khushi1787, 1 year ago

the digits pf a two-digit number differ by 3. If the digits are intercharged and the resulting number is added to the original number, we get 143. The What can be the original number?

Answers

Answered by CoruscatingGarçon
2

Let the digits be x and x+3.

10x+x+3+10x+30+x=143

22x+33=143

22x=110

X=5

X+3=8

The number is 58(or 85 if we take x and  x-3)

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