the digits pf a two-digit number differ by 3. If the digits are intercharged and the resulting number is added to the original number, we get 143. The What can be the original number?
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Let the digits be x and x+3.
10x+x+3+10x+30+x=143
22x+33=143
22x=110
X=5
X+3=8
The number is 58(or 85 if we take x and x-3)
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