Question

the dignols of the rohumbous measure 16 cm and 30 cm . find it's perimeter​

Answer 1

Answer:

hey mate,

ur answer is below

Step-by-step explanation:

we can say that 8 cm +8 cm = 16 cm and 15 cm + 15 cm = 30 cm...

since diagonal of a rhombus bisects each other

now by applying the Pythagoras theorem we get,

h² = p² + b²

h² = 8² + 15²

h² = 64 + 225

h² = 289

h = √289

h = 17

therefore perimeter of the rhombus ,  

= 4 * side

= 4 * 17

= 68 cm

therefore perimeter of the rhombus = 68 cm

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