Question

The diluted wine contains only 8 liters of wine and the rest is water. A new mixture whose concentration is 30%, is to be formed by replacing wine. How many liters of mixture shall be replaced with pure wine if there was initially 32 liters of water in the mixture ?
A) 4
B) 5
C) 8
D) None of these

Answer 1

The diluted wine contains only 8 liters of wine and the rest is water. A new mixture whose concentration is 30%, is to be formed by replacing wine. How many liters of mixture shall be replaced with pure wine if there was initially 32 liters of water in the mixture ?
A) 4
B) 5✔
C) 8
D) None of these


ĀNSWĒR ⏬⏬


B.5


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# NAVI ❤ HARYANVI ♠

Answer 2

#RAM RAM ji ❤



Answer:   B) 5 

Explanation:

           Wine                         Water

            8L                              32L

            1                :               4

           20 %                           80%

           30 %                           70%


 

so the ratio of left quantity to the initial quantity is 7:8

 

Therefore , 78=[1−K/40]


=> K = 5 Lit



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#Nishu HaRYanvi♠