Math, asked by akshayghusalkar, 2 months ago

The diluted wine contains only 8 litres
of wine and the rest is water. A new
mixture whose concentration is 30%, is
to be formed by replacing wine. How
many litres of mixture shall be replaced
with pure wine if there was initially 32
litres of water in the mixture?​

Answers

Answered by milindkhanna33
0

Answer:

5

Step-by-step explanation:

Wine Water

8L 32L

1 : 4

20 % 80% (original ratio)

30 % 70% (required ratio)

In ths case, the percentage of water being reduced when the mixture is being replaced with wine.

so the ratio of left quantity to the initial quantity is 7:8

Therefore , [Math Processing Error]78=1-

=> K = 5 Lit

Answered by kedartoraskar758
0

Step-by-step explanation:

Hope it helps you please Mark my answer as brainlist

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