The diluted wine contains only 8 litres
of wine and the rest is water. A new
mixture whose concentration is 30%, is
to be formed by replacing wine. How
many litres of mixture shall be replaced
with pure wine if there was initially 32
litres of water in the mixture?
Answers
Answered by
0
Answer:
5
Step-by-step explanation:
Wine Water
8L 32L
1 : 4
20 % 80% (original ratio)
30 % 70% (required ratio)
In ths case, the percentage of water being reduced when the mixture is being replaced with wine.
so the ratio of left quantity to the initial quantity is 7:8
Therefore , [Math Processing Error]78=1-
=> K = 5 Lit
Answered by
0
Step-by-step explanation:
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