The dimension ML⁻¹T⁻² can correspond to
(a) moment of a force
(b) surface tension
(c) modulus of elasticity
(d) coefficient of viscosity.
Answers
Answered by
9
For Option (a).
Moment of Force or Torque = Perpendicular distance × Force
∴ Dimension Formula of τ = L × MLT⁻² = ML²T⁻²
For Option (b).
Surface Tension = Force = MLT⁻²
For Option (c).
Modulus of Elasticity = Stress/Strain.
∴ Dimensional formula of modulus of Elasticity = Force/Area
= MLT⁻²/L²
= ML⁻¹T⁻²
This is same as that asked in question.
Therefore It is the Correct answer.
The Dimension of Coefficient of viscosity is ML⁻¹T⁻¹.
Hope it helps.
Answered by
3
For Option (a).
Moment of Force or Torque = Perpendicular distance × Force
∴ Dimension Formula of τ = L × MLT⁻² = ML²T⁻²
For Option (b).
Surface Tension = Force = MLT⁻²
For Option (c).
Modulus of Elasticity = Stress/Strain.
∴ Dimensional formula of modulus of Elasticity = Force/Area
= MLT⁻²/L²
= ML⁻¹T⁻²
This is same as that asked in question.
Therefore It is the Correct answer.
The Dimension of Coefficient of viscosity is ML⁻¹T⁻¹.
Moment of Force or Torque = Perpendicular distance × Force
∴ Dimension Formula of τ = L × MLT⁻² = ML²T⁻²
For Option (b).
Surface Tension = Force = MLT⁻²
For Option (c).
Modulus of Elasticity = Stress/Strain.
∴ Dimensional formula of modulus of Elasticity = Force/Area
= MLT⁻²/L²
= ML⁻¹T⁻²
This is same as that asked in question.
Therefore It is the Correct answer.
The Dimension of Coefficient of viscosity is ML⁻¹T⁻¹.
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