Physics, asked by samarthmihir2005, 5 hours ago

The dimension of 1/2ε0E², where ε0 is permittivity of free space and E is electric field is

Answers

Answered by mujeebuddinahmed843

The answer is ML-1T-2

Energy density of an electric field E is uE = 1/2 ɛ0E2 where ɛ0 is permittivity of free space uE = Energy/Volume = ML2T-2/L3 = ML-1T-2 Hence, the dimension of 1/2ɛ0E2 is ML-1T-2

hope it helps•••

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