Question

The dimension of a block is 100m×1 m× 1 m . The specific resistance of the material of the block is 4×10^6 ohm meter. Calculate its resistance across its square faces.

Answer 1

Answer:

The resistance across its square faces is $R=4 \times 10^8\ \Omega$ .

Explanation:

Given :

Dimensions of block is 100 m×1  m× 1 m .

Specific resistance of the material of the block is , $\rho=4\times 10^6\ \Omega \ m$ .

We need to find the resistance across its square faces.

Therefore , length of resistance is , l = 100 m .

Area of square face

$A=1\times 1\ m^2\\A=1\ m^2$

Know , we know resistance is given by :

$R=\dfrac{\rho \times l }{A}$

Putting all value in above equation .

We get :

$R=\dfrac{4 \times 10^6 \times 100 }{1} \\\\R=4 \times 10^8\ \Omega$

Therefore , the value of resistance across its square faces is $R=4 \times 10^8\ \Omega$ .