the dimension of a box are 60cn multiple 54cm multiple 30cm. how many small cubes of side 6cm can be placed in the box
Answers
Answered by
24
Heya!!
Dimension of cuboidal box:
length = 60 cm
breadth= 54 cm
height= 30 cm
Dimension of cubical cubes:
side= 6 cm
____________________________
Now,
No of small cubes = vol of cuboidal box/ vol of cubical box
= 60 × 54 × 30/ 6 × 6 × 6
= 10 × 9 × 5
= 450
Hence, the number of cubes which can be placed in box is 450.
Hope ut helps uh:)
Dimension of cuboidal box:
length = 60 cm
breadth= 54 cm
height= 30 cm
Dimension of cubical cubes:
side= 6 cm
____________________________
Now,
No of small cubes = vol of cuboidal box/ vol of cubical box
= 60 × 54 × 30/ 6 × 6 × 6
= 10 × 9 × 5
= 450
Hence, the number of cubes which can be placed in box is 450.
Hope ut helps uh:)
anurag00793:
thanks
Answered by
25
Given,
Length of the box, l = 60 cm
Breadth of the box, b = 54 cm
Height of the box, h = 30 cm
Hence,
Volume of the box, V = Length * Breadth * Height
V = l * b * h
V = 60 * 54 * 30
V = 1800 * 54
V = 97200 cm^3
Now,
Side of each of the smaller cubes = 6 cm
Therefore,
Volume of each smaller cube, v = ( side ) ^ 3
v = 6 ^ 3
v = 216 cm^3
Now,
The required number of cubes, n = 97200 / 216
On simplifying further we get,
n = 450
Hence,
The required number of cubes = 450
Length of the box, l = 60 cm
Breadth of the box, b = 54 cm
Height of the box, h = 30 cm
Hence,
Volume of the box, V = Length * Breadth * Height
V = l * b * h
V = 60 * 54 * 30
V = 1800 * 54
V = 97200 cm^3
Now,
Side of each of the smaller cubes = 6 cm
Therefore,
Volume of each smaller cube, v = ( side ) ^ 3
v = 6 ^ 3
v = 216 cm^3
Now,
The required number of cubes, n = 97200 / 216
On simplifying further we get,
n = 450
Hence,
The required number of cubes = 450
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