Question

THE DIMENSION OF A FIELD ARE 15m BY 12m.A pit 7.5m long, 6m wide and 1.5m deep is dug at one corner of the field. The earth removed is evenly is evenly spread over the remaining area of the field. Calculate the rise in the level of the field.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$Rise\: in \:the\: level\\ in\: the\: remaining\: field\\ =0.5\:m$

Step-by-step explanation:

Dimensions of a field:

Length (L)=15 m,

Breadth (B)=12 m,

Dimensions of the Pit:

length (l)= 7.5 m,

width (b)=6 m,

depth (h)=1.5 m,

According to the problem given,

If the pit is dug at one corner of the field and earth removed is evenly spread over the remaining area of the field.

Now,

Area of the remaining field

= Area of the field - base area of the pit

= LB - lb

= 15 × 12 - 7.5 × 6

= 180 m² - 45 m²

= 135 m²

$Let\: rise\: in \:the\: level\\ in\: the\: remaining\: field\\ = \frac{Volume \: of \: the\:pit}{Area\:of\:the\: remaining\:field}$

$=\frac{7.5\times 6\times 1.5\: m^{3}}{135 \:m^{2}}\\=0.5\:m$

Therefore,

$Rise\: in \:the\: level\\ in\: the\: remaining\: field\\ =0.5\:m$

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