The dimension of a hall is 4.8m × 3.6m what is the number of tiles required to cover with size of 1.2 m tiles
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12
dimension of hall is = 4.8 m into 3.6 m
area of hall 4.8 × 3.6 m is =17. 28 sq. m
if per tiles covers = 1.2 m
so , number of tiles
required =1.2×1.2= 1.44 sq. m
17.28÷1.44=
required 12 tiles.
area of hall 4.8 × 3.6 m is =17. 28 sq. m
if per tiles covers = 1.2 m
so , number of tiles
required =1.2×1.2= 1.44 sq. m
17.28÷1.44=
required 12 tiles.
Answered by
8
Answer:
Step-by-step explanation:
Dimensions of the hall= 4.8m and 3.6m
Area of Hall= l x b
= 4.8x3.6= 17.28m^2
Area of tile=s x s
1.2x1.2
1.44m^2
No. of tiles= area of Hall/ area of tile
17.28/1.44
12 tiles
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