the dimension of a rectangle ABCD are 51 cm × 25 CM . A Trapezium PQCD with its parallel sides QC and PD are in the ratio of 9:8, is cut off from the rectangle as shown in figure .If the area of trapezium PQCD is 5/6 part of the area of a rectangle find QC and PD.
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Answer:
Qc=45 pd=40
Step-by-step explanation:
qc/pd=9/8 or pd=8*qc/9
area pqcd=5*25*51/6
qc*25+25*(pd-qc)/2=5*25*51/6
25qc+25/2*(8qc/9-qc)=5*25*17/2
by solving above
qc=45
pd=8*45/9=40
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