Question

the dimension of a room 12m×4m × 3m .find the maximum lenght of a iron rod that can be placed in this room...

Answer 1

maximum length=diagonal
d=√w^2+l^2
=√4^2+12^2=√16+144=√158m

Answer 2

Here the maximum length of the rod refers to the diagonal of the cuboidal room:

Diagonal of the cuboid = √l²+b²+h²

On substituting the given values, we get:

√12²+4²+3²

= √144 + 16+ 9

= √169

= 13 m

Therefore the maximum length of the rod is 13 m.