The dimension of a room are (16×14×19)m. There are 4 Windows of *1.3×1.4)m and 2 doors of (2×1)m what will be the cost of while washing is rs 5/m^2 and the rate of painting is rs8/m^2.solve short question.
Answers
AnswEr :
- Room = (16m × 14m × 19m)
- Window = (1.3m × 1.4m) Each
- Door = (2m × 1m) Each
As we have to find the Cost of white washing and painting, that will be done on four walls only i.e. Curved Surface Area.
• Let's Head to the Question Now :
↠ Area Required = CSA of Walls – (Area of 4 windows + Area of 2 Doors)
↠ Area Required = [2(l + b) × h] – [(4 × lb) + (2 × lb)]
↠ Area Required = [2(16 + 14) × 19)] – [(4 × 1.3 × 1.4) + (2 × 2 × 1)]
↠ Area Required = [2 × 30 × 19] – [7.28 + 4]
↠ Area Required = [1140m² – 11.28m²]
↠ Area Required = 1128.72 m²
◗ Area Required to work on is 1128.72 m²
━━━━━━━━━━━━━━━━━━━━━━━━
• COST OF WHITE WASHING :
⇒ Cost = Area Required × Rate
⇒ Cost = 1128.72 m² × Rs. 5 @m²
⇒ Cost = Rs. 5643.60
∴ Cost of white washing is Rs. 5643.60
_______________________________
• COST OF PAINTING THE WALLS :
⇒ Cost = Area Required × Rate
⇒ Cost = 1128.72 m² × Rs. 8 @m²
⇒ Cost = Rs. 9029.76
∴ Cost of Painting of walls is Rs. 9029.76
#answerwithquality #BAL
Answer:
The room has dimensions of 16 m by 14 m by 10 m.
So, the area of the four walls (including the doors and windows) of the room will be = 2(L + W)H = 2(16 + 14) × 10 = 600 sq. meters.
Now the total area of four windows and two doors = 4(1.3 × 1.4) + 2(2 × 1) = 11.28 sq. meters.
So, the painting cost of the doors and windows at the rate of 8 Rs. per sq, meters will be (11.28 × 8) = 90.24 Rs.
Now, the area of the wall excluding the doors and windows is (600 - 11.28) = 588.72 sq. meters.
Hence, the cost of whitewashing the wall at a rate of 5 Rs. per sq. meters will be (588.72 × 5) = 2943.6 Rs.
Therefore, the total cost of painting and whitewashing will be (2943.6 + 90.24) = Rs. 3033.84. (Answer)